document.write( "Question 1143059: 12b²-29b+15
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Algebra.Com's Answer #763822 by Theo(13342) You can put this solution on YOUR website! expression is 12b^2 - 29b + 15\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "set the expression equal to 0 to get the equation of 12b^2 - 29b + 15 = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "replace b with x to get the equation of 12x^2 - 29x + 15 = 0.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "use the quadratic formula to solve for x in this quadratic equation that is now in standard form of ax^2 + bx + c = 0.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "a = 12 \n" ); document.write( "b = -29 \n" ); document.write( "c = 15\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "quadratic formula is x = (-b + sqrt(b^2-4ac)/(2a) or x = (-b - sqrt(b^2-4ac)/(2a)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "first formula becomes x = (29 + 11) / 24 = 5/3.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "second formula becomes x = (29 - 11) / 24 = 3/4.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "those are the roots of the given equation.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "replace x with b and you get b = 5/3 or b = 3/4.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |