document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1143042>Question 1143042</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Statistics\r<BR>\n" );
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document.write( "A human gene carries a certain disease from the mother to the child with a probability rate of forty percent (40%).  That is, there is a 40% chance that the child becomes infected with the disease.  Suppose a female carrier of the gene has three children.  Assume that the infections of the three children are independent of one another.  Find the probability that at least one of the children get the disease from their mother.  <BR>\n" );
document.write( "a.  0.216<BR>\n" );
document.write( "b.  0.784<BR>\n" );
document.write( "c.  0.432<BR>\n" );
document.write( "d.  0.144 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #763793 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=763793\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the probability than none get the disease.  That is 0.6^3=0.216<BR>\n" );
document.write( "The probability of at least 1 is 1 minus the probability none got it or 1-0.216=0.784.<BR>\n" );
document.write( "B.<BR>\n" );
document.write( "This is easier than doing the probability of 1 or 2 or all 3. </SPAN>\n" );
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