document.write( "Question 1143037: How many gallons each of 25​% alcohol and 5​% alcohol should be mixed to obtain 20 gal of 16​% ​alcohol? \n" ); document.write( "
Algebra.Com's Answer #763782 by Boreal(15235)\"\" \"About 
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x gal of 25%
\n" ); document.write( "20-x gal of 5%
\n" ); document.write( "pure alcohol is x(.25)+(20-x)(.05)=20*.16=3.2
\n" ); document.write( "so .25x+1-.05x=3.2 gallons of 25%
\n" ); document.write( ".20x=2.2 gallons of 5%
\n" ); document.write( "x=11 gallons of 25% or 2.75 gallons of pure alcohol
\n" ); document.write( "20-x=9 gallons of 5% or 0.45 gallons of pure
\n" ); document.write( "That equals 3.2 gallons pure, checks.
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