document.write( "Question 1143037: How many gallons each of 25% alcohol and 5% alcohol should be mixed to obtain 20 gal of 16% alcohol? \n" ); document.write( "
Algebra.Com's Answer #763782 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! x gal of 25% \n" ); document.write( "20-x gal of 5% \n" ); document.write( "pure alcohol is x(.25)+(20-x)(.05)=20*.16=3.2 \n" ); document.write( "so .25x+1-.05x=3.2 gallons of 25% \n" ); document.write( ".20x=2.2 gallons of 5% \n" ); document.write( "x=11 gallons of 25% or 2.75 gallons of pure alcohol \n" ); document.write( "20-x=9 gallons of 5% or 0.45 gallons of pure \n" ); document.write( "That equals 3.2 gallons pure, checks. \n" ); document.write( " |