document.write( "Question 1143040: Brian and Daryl went shopping. both decided to spend the 532 pesos they have saved from their allowance. Daryl spent 1/2 of her money. After Brian spent 82 pesos,they had the same amount of money left. How much money did Brian have at first? \n" ); document.write( "
Algebra.Com's Answer #763779 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! Brian had x \n" ); document.write( "Daryl had 532-x \n" ); document.write( "Daryl spent (532-x)/2 \n" ); document.write( "Brian spent 82 \n" ); document.write( "B now has x-82 \n" ); document.write( "Daryl now has (532-x)/2 \n" ); document.write( "those are equal \n" ); document.write( "multiply both sides by 2 \n" ); document.write( "2(x-82)=532-x \n" ); document.write( "2x-164=532-x \n" ); document.write( "3x=696 \n" ); document.write( "x=232 for Brian \n" ); document.write( "Daryl has 532-232=300\r \n" ); document.write( "\n" ); document.write( "Brian spent 82 and has 150 \n" ); document.write( "Daryl has half of 300 or 150 \n" ); document.write( " |