document.write( "Question 1143040: Brian and Daryl went shopping. both decided to spend the 532 pesos they have saved from their allowance. Daryl spent 1/2 of her money. After Brian spent 82 pesos,they had the same amount of money left. How much money did Brian have at first? \n" ); document.write( "
Algebra.Com's Answer #763779 by Boreal(15235)\"\" \"About 
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Brian had x
\n" ); document.write( "Daryl had 532-x
\n" ); document.write( "Daryl spent (532-x)/2
\n" ); document.write( "Brian spent 82
\n" ); document.write( "B now has x-82
\n" ); document.write( "Daryl now has (532-x)/2
\n" ); document.write( "those are equal
\n" ); document.write( "multiply both sides by 2
\n" ); document.write( "2(x-82)=532-x
\n" ); document.write( "2x-164=532-x
\n" ); document.write( "3x=696
\n" ); document.write( "x=232 for Brian
\n" ); document.write( "Daryl has 532-232=300\r
\n" ); document.write( "\n" ); document.write( "Brian spent 82 and has 150
\n" ); document.write( "Daryl has half of 300 or 150
\n" ); document.write( "
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