document.write( "Question 1142897: There are 30 red balls and 20 green balls and some blue balls in a bag. If the probility of finding a red ball is 1/3. How many are red balls in the bag \n" ); document.write( "
Algebra.Com's Answer #763632 by ikleyn(52787)\"\" \"About 
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\n" ); document.write( "There are 30 red balls and 20 green balls and some blue balls in a bag. If the probility of finding a red ball is 1/3.
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\n" ); document.write( "\n" ); document.write( "            The original formulation is  INCORRECT  and nonsensical,  since the number of red balls is just  GIVEN.\r
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\n" ); document.write( "\n" ); document.write( "            To make sense,  the problem  MUST  BE  RE-FORMULATED.  For example,  in  THIS  WAY :\r
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document.write( "             There are 30 red balls and 20 green balls and some blue balls in a bag. \r\n" );
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document.write( "             If the probability of finding a \"highlight%28cross%28red%29%29\" blue ball is 1/3,  how many \"highlight%28cross%28red%29%29\" blue balls are there in the bag ?\r\n" );
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\n" ); document.write( "\n" ); document.write( "            For such formulated problem,  the solution is as follows.\r
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document.write( "\"x%2F%2830+%2B+20+%2B+x%29\" = \"1%2F3\"  =====>\r\n" );
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document.write( "3x = 30 + 20 + x\r\n" );
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document.write( "2x = 50\r\n" );
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document.write( "x = 50/2 = 25   blue balls.      ANSWER\r\n" );
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