document.write( "Question 1142816: The period of a particle moving in SHM is 6 seconds and its amplitude is 8cm. Calculate its velocity and acceleration to 1dp when the particle is 5cm from the centre of motion.\r
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Algebra.Com's Answer #763566 by ikleyn(52851)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "By changing the origin for the time, you may forget about \"alpha\" and write the formula for SHM in the form\r\n" );
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document.write( "    x = \"8%2Acos%28%28pi%2F3%29%2At%29\".\r\n" );
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document.write( "It is totally enough to solve the problem.\r\n" );
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document.write( "Now, when x= 5 cm, you have  5 = \"8%2Acos%28%28pi%2F3%29%2At%29\", or\r\n" );
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document.write( "    \"cos%28%28pi%2F3%29%2At%29\" = \"5%2F8\".\r\n" );
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document.write( "Next, the velocity is the DERIVATIVE of the position function x = x(t)\r\n" );
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document.write( "    Velocity = \"d%2F%28dt%29\"(\"8%2Acos%28%28pi%2F3%29%2At%29\") = \"-8%2A%28pi%2F3%29%2Asin%28%28pi%2F3%29%2At%29\".\r\n" );
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document.write( "You just know the cosine function  \"cos%28%28pi%2F3%29%2At%29\"  from (1) - so you can calculate \r\n" );
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document.write( "    \"sin%28%28pi%2F3%29%2At%29\" = \"sqrt%281-%285%2F8%29%5E2%29\".\r\n" );
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document.write( "In this way, you can complete calculations for velocity.\r\n" );
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document.write( "Then for acceleration, use the fact that it is THE SECOND DERVATIVE of the position function and do the same.\r\n" );
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\n" ); document.write( "\n" ); document.write( "If you still have difficulties/questions, let me know by posting your message through the \"Thank you\" window.\r
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\n" ); document.write( "\n" ); document.write( "In this case, refer to the problems ID number, which is 1142816.\r
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