document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1142826>Question 1142826</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the standard equation of the circle which has (-1,3) and (2,4) as the end points of a diameter\r<BR>\n" );
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document.write( "I followed a YouTube tutorial and want to make sure that I am right<BR>\n" );
document.write( "So I used the midpoint formula (-1+3)/2,(2+4)/2= (1,3)<BR>\n" );
document.write( "Then I used the formula for finding the radius r=1/2squareroot of (2-(-1)^2+(4-3)^2 I evualated it then got squareoot of 5/2<BR>\n" );
document.write( "And r^2=(5/2)^2 = 5/4<BR>\n" );
document.write( "And I got the standard equation (x-1)^2+(y-3)^2= 5/4<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #763558 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13203)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=763558\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Your midpoint and radius are both incorrect.<br><BR>\n" );
document.write( "The midpoint formula finds the x coordinate of the midpoint as the average of the x coordinates of the two endpoints and the y coordinate of the midpoint as the average of the y coordinates of the two endpoints.  You didn't do that.<br><BR>\n" );
document.write( "The calculation you show for the radius is correct; but you didn't evaluate it correctly.<br><BR>\n" );
document.write( "Look at your work again and see if you can correct your errors; post a \"thank you\" note if you need more help, explaining or demonstrating what it is you need help with. </SPAN>\n" );
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