document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1142827>Question 1142827</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the diameter of a circle is P and P^2/4 =2whag is the area is the circle! <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #763557 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=763557\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><PRE STYLE=\"white-space: pre-wrap; white-space: -moz-pre-wrap; white-space: -pre-wrap; white-space: -o-pre-wrap; word-wrap: break-word;\">\r\n" );
document.write( "Area = (pi)(r^2)  formula for area of a circle\r\n" );
document.write( "     = (pi)((P/2)^2)  the radius is half the diameter, which is P\r\n" );
document.write( "     = (pi)(P^2/4)  simplify\r\n" );
document.write( "     = (pi)(2)  it is given that P^2/4 = 2\r\n" );
document.write( "     = 2pi</PRE><br> </SPAN>\n" );
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