document.write( "Question 1142817: The figure represents an empty cube with a circular opening at the top. The diameter of the opening is half the length of diagonal AB. The outer surface area of cube in square centimetres is \n" ); document.write( "
Algebra.Com's Answer #763551 by josgarithmetic(39617)\"\" \"About 
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\n" ); document.write( "Assuming diagonal AB is for one side of the cube,\r
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\n" ); document.write( "\n" ); document.write( "Diameter of the empty circle is half of AB
\n" ); document.write( "Diameter is \"%28AB%29%2F2\"\r
\n" ); document.write( "\n" ); document.write( "r, radius of circular opening
\n" ); document.write( "\"r=%28AB%29%2F4\"\r
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\n" ); document.write( "\n" ); document.write( "Looking at one side having diagonal AB,
\n" ); document.write( "side length.... \"cross%28sqrt%282%29%28AB%29%2F2%29\"\r
\n" ); document.write( "\n" ); document.write( "..
\n" ); document.write( "..\r
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\n" ); document.write( "\n" ); document.write( "Outer surface area of the cube:
\n" ); document.write( "Simplify this.\r
\n" ); document.write( "\n" ); document.write( "\"6%28%28AB%29%2F2%29%5E2-pi%28%28AB%29%2F4%29\"
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