document.write( "Question 1142764: Calculus Question\r
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Algebra.Com's Answer #763495 by ikleyn(52802) $\"\"$ $\"About$

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document.write( " = 12xy\r\n" );
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document.write( "Differentiate, considering y as a function of x, y = y(x) :\r\n" );
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document.write( "    3x^2 + 3y^2*y' = 12y + 12x*y'\r\n" );
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document.write( "Collect the terms with y' in one side;  the terms with no y' in the other side :\r\n" );
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document.write( "     3y^2*y' - 12x*y' = 12y - 3x^2\r\n" );
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document.write( "     y'*(3y^2 - 12x) = .\r\n" );
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document.write( "Express  y' :\r\n" );
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document.write( "     y' = ,   \r\n" );
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document.write( "or,  canceling the common factor 3 in the numerator and in the denominator,\r\n" );
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document.write( "     y' = ,   \r\n" );
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document.write( "It is your answer.\r\n" );
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