document.write( "Question 1142767: What is Aman's present age, if after 20 years his age will be 10 times his age 10 years back?
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Algebra.Com's Answer #763493 by ikleyn(52797) $\"\"$ $\"About$

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document.write( "A + 20 = 10*(A-10)\r\n" );
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document.write( "A + 20 = 10A - 100\r\n" );
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document.write( "20 + 100 = 10A - A\r\n" );
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document.write( "120 = 9A\r\n" );
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document.write( "A = .\r\n" );
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document.write( "Do you see here an integer solution ?\r\n" );
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document.write( "I do not see it, too.\r\n" );
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document.write( "Hence, the problem is DEFECTIVE, by the definition.\r\n" );
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\n" ); document.write( "\n" ); document.write( "John pointed me that one third of the year is 4 months.\r
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\n" ); document.write( "\n" ); document.write( "First, I am very glad that John returned back to the forum (!)\r
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\n" ); document.write( "\n" ); document.write( "Second, the months are of UNEQUAL time length, so it has no much sense to say that one third of the year is 4 months.\r
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\n" ); document.write( "\n" ); document.write( "It depends on which month / (what months) and which year.\r
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\n" ); document.write( "\n" ); document.write( "My diagnosis remains the same: if in \"age word problem\" the answer is not an integer, \r
\n" ); document.write( "\n" ); document.write( "then such a problem is DEFECTIVE by the definition.\r
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