document.write( "Question 1142729: Hello,I'd like help on this question
\n" ); document.write( "Factor f(x)=4x^3+11x^2-40x+25 into linear factors given that −5 is a zero of f(x).\r
\n" ); document.write( "\n" ); document.write( "Thank you \n" ); document.write( "

Algebra.Com's Answer #763453 by josgarithmetic(39618) $\"\"$ $\"About$

You can put this solution on YOUR website!
f(x)=4x^3+11x^2-40x+25 into linear factors given that −5 is a zero\r
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\r\n" );
document.write( "-5   |   4   11   -40   25\r\n" );
document.write( "     |\r\n" );
document.write( "     |      -20    45   -25\r\n" );
document.write( "     ---------------------------------\r\n" );
document.write( "         4  -9    5     0\r\n" );
document.write( "

\r
\n" ); document.write( "\n" ); document.write( " $\"f%28x%29=%28x%2B5%29%284x%5E2-9x%2B5%29\"$ \r
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\n" ); document.write( "\n" ); document.write( "Zeros of the quadratic factor:
\n" ); document.write( " $\"%289%2B-+sqrt%2881-4%2A4%2A5%29%29%2F%282%2A4%29\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"%289%2B-+1%29%2F8\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"system%281%2C+and%2C+5%2F4%29\"$ \r
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\n" ); document.write( "\n" ); document.write( "Try testing for $\"1\"$ as a zero.
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\r\n" );
document.write( "1   |   4    -9    5\r\n" );
document.write( "     |\r\n" );
document.write( "     |        4    -5\r\n" );
document.write( "     |------------------------\r\n" );
document.write( "        4    -5    0\r\n" );
document.write( "

\n" ); document.write( "This means $\"4x-5\"$ is also a linear factor.\r
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\n" ); document.write( "\n" ); document.write( " $\"highlight%28f%28x%29=%28x%2B5%29%28x-1%29%284x-5%29%29\"$ \n" ); document.write( "

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