document.write( "Question 1142724: I am trying to calculate a probability problem. It reads: \"If someone spins the spinner twice, what is the probability it will land on an even number?\"\r
\n" ); document.write( "\n" ); document.write( "The spinner has the following numbers clockwise: 1,2,3,2,5,4,4. However, the space that includes the 1 is twice the size of the others and is 25% of the total area of the spinner. If I draw a dividing line in the larger space, I will then have 8 equal parts. Is this the correct procedure for solving the problem?
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Algebra.Com's Answer #763444 by Theo(13342)\"\" \"About 
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the probability that the spinner will land anywhere on the spinner board is considered to be equal.\r
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\n" ); document.write( "\n" ); document.write( "since the number 1 space is 25% of the area of the board, then the other numbers, being equally spaced, represent 75% of the area of the board.\r
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\n" ); document.write( "\n" ); document.write( "you have 6 other numbers.
\n" ); document.write( "75% / 6 = 12.5\r
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\n" ); document.write( "\n" ); document.write( "each of the other numbers takes up 12.5% of the area of the board.
\n" ); document.write( "if you split the 1 into 2 spaces, then each one of the number 1's will also take up 12.5% of the board.\r
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\n" ); document.write( "\n" ); document.write( "it sounds like your method will work.\r
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\n" ); document.write( "\n" ); document.write( "the numbers on the board are then 1,1,2,3,2,5,4,4.\r
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\n" ); document.write( "\n" ); document.write( "each of those numbers takes up 12.5% of the area of the board.\r
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\n" ); document.write( "\n" ); document.write( "4 of the numbers are even and 4 of the numbers are odd.\r
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\n" ); document.write( "\n" ); document.write( "the probability that the spinner will land on an even number is therefore 4 / 8 = 50%.\r
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\n" ); document.write( "\n" ); document.write( "the probability that the spinner will land on an odd number is therefore also 4 / 8 = 50%.\r
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\n" ); document.write( "\n" ); document.write( "on your first spin, the probability that it will land on an even number is .5.\r
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\n" ); document.write( "\n" ); document.write( "on your second spin, the probability that it will land on an even number is also .5.\r
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\n" ); document.write( "\n" ); document.write( "the probability that it will land on an even number both times is therefore .5 * .5 = .25.\r
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\n" ); document.write( "\n" ); document.write( "there is another way to look at it.\r
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\n" ); document.write( "\n" ); document.write( "the number 1 takes up 25% of the board space.
\n" ); document.write( "the number 3 takes up 12.5% of the board space.
\n" ); document.write( "the number 5 takes up 12.5% of the board space.\r
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\n" ); document.write( "\n" ); document.write( "all the odd numbers take up 50% of the board.
\n" ); document.write( "all the even numbers take up 50% of the board.
\n" ); document.write( "same probabilities.\r
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