document.write( "Question 1142695: A coffee merchant blended coffee worth 93 cents a pound with coffee worth $1.20 a pound. The mixture of 30 pounds was valued by him at $1.02 a pound. How many pounds of each grade did he use?\r
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Algebra.Com's Answer #763439 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "A coffee merchant blended coffee worth 93 cents a pound with coffee worth $1.20 a pound. The mixture of 30 pounds was valued by him at $1.02 a pound. How many pounds of each grade did he use?
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\n" ); document.write( "\n" ); document.write( "L = 0.93 dollars per pound
\n" ); document.write( "H = 1.02 dollars per pound
\n" ); document.write( "T = 1.02
\n" ); document.write( "M = 30 pounds
\n" ); document.write( "y, unknown amount in pounds for the H coffee
\n" ); document.write( "M-y, unknown amount of L coffee\r
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\n" ); document.write( "\n" ); document.write( "\"highlight_green%28L%28M-y%29%2BHy=TM%29\"
\n" ); document.write( "Solve for y, and evaluate M-y.\r
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\n" ); document.write( "\n" ); document.write( "\"LM-Ly%2BHy=TM\"\r
\n" ); document.write( "\n" ); document.write( "\"Hy-Ly%2BLM=TM\"\r
\n" ); document.write( "\n" ); document.write( "\"%28H-L%29y=TM-LM\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28y=%28TM-LM%29%2F%28H-L%29%29\"------substitute the given values here and evaluate y.
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