document.write( "Question 1142661: A case of 24 cans contains 1 can that is contaminated. Three cans are to be chosen randomly for testing.
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Algebra.Com's Answer #763368 by ikleyn(53937)\"\" \"About 
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document.write( "(a)  \"C%5B24%5D%5E3\" = \"%28%2824%2A23%2A22%29%2F%281%2A2%2A3%29%29\" = 2024 different combinations of 3 cans.\r\n" );
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document.write( "(b)   \"C%5B24-1%5D%5E2\" = \"C%5B23%5D%5E2\" = \"%28%2823%2A22%29%2F%281%2A2%29%29\" = 253 different combinations of 3 cans, containing the contaminated one.\r\n" );
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document.write( "      (You can form all possible combinations by adding any two other cans to the contaminated one).\r\n" );
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document.write( "      The probability is  \"253%2F2024\" = 0.125.\r\n" );
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