document.write( "Question 1142647: A bag contains 2 red, 4 green, and 5 yellow m&m. Find the probability of drawing at least one green m&m. Write answer as a fraction. \n" ); document.write( "

Algebra.Com's Answer #763347 by ikleyn(52915) $\"\"$ $\"About$

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\n" ); document.write( "A bag contains 2 red, 4 green, and 5 yellow m&m. Find the probability of drawing at least one green m&m. Write answer as a fraction.
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\n" ); document.write( "\n" ); document.write( "As the problem is printed, written, posted and presented, it MAKES NO SENSE.\r
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\n" ); document.write( "\n" ); document.write( "To be correct, the formulation should point on HOW MANY m&m's are taken off (= are drawn out) at a time .\r
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\n" ); document.write( "comment from student: A bag contains 2 red, 4 green, and 5 yellow m&m. Two are randomly drawn in succession, without replacement.
\n" ); document.write( "Find the probability of drawing at least one green m&m. Write answer as a fraction.
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\n" ); document.write( "\n" ); document.write( "My response :\r
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\n" ); document.write( "\n" ); document.write( "            O ! This corrected formulation totally changes everything !\r
\n" ); document.write( "\n" ); document.write( "            Now it is a good, reasonable and fine Math problem.\r
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\n" ); document.write( "\n" ); document.write( "            The solutions is as follows.\r
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document.write( "To solve the problem, let's consider the complement set of events.\r\n" );
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document.write( "The complement set of events is to get no one green m&m when drawing randomly two m&m in succession.\r\n" );
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document.write( "It means that selection is made, actually, among the subset of 2 red and 5 yellow m&m.\r\n" );
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document.write( "This subset contains 2+5 = 7 m&m's, and the number of different pairs among them is   =  = 21.\r\n" );
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document.write( "The total number of different pairs of m&m's in the whole set of 2 red, 4 green, and 5 yellow m&m is\r\n" );
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document.write( "     =  =  = 55.\r\n" );
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document.write( "So, the probability of not getting a green m&m  is  .\r\n" );
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document.write( "Therefore, the complement probability to get at least one m&m is  \r\n" );
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document.write( "    1 -  =  = .    ANSWER\r\n" );
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\n" ); document.write( "\n" ); document.write( "Solved.\r
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