document.write( "Question 1142626: the top of a building is a rectangle whose length is 60ft.more than the width.the perimeter 520 ft. find the length and the width \n" ); document.write( "
Algebra.Com's Answer #763313 by ikleyn(52887) You can put this solution on YOUR website! . \n" ); document.write( " \r\n" ); document.write( "\r\n" ); document.write( "W + (W+60) = 520/2\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "2W + 60 = 260\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "2W = 260 - 60\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "2W = 200\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "W = 100.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "ANSWER. The width is 100 ft; the length is 100+60 = 160 ft.\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |