document.write( "Question 1142602: I am stumped on this one, can someone help me out? I think I am overthinking this. I have literally stared at this and I have no Idea which way to go with it-- TIA\r
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\n" ); document.write( "Matthew Plant has $36000 invested in stock A and stock B. Stock A currently sells for $40 a share and stock B sells for $60 a share. If stock B doubles in value and stock A goes up 50%, his stock will be worth $66000. How many shares of each stock does he own? \n" ); document.write( "

Algebra.Com's Answer #763284 by ikleyn(52781) $\"\"$ $\"About$

You can put this solution on YOUR website!
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document.write( "Let \"n\" be the number of stocks A and \"m\" be the number of stocks B.\r\n" );
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document.write( "Then from the condition you have this system of 2 equations in 2 unknowns\r\n" );
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document.write( "        40*n +   60*m = 36000    (1)\r\n" );
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document.write( "    1.5*40*n + 2*60*m = 66000.   (2)\r\n" );
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document.write( "Simplify\r\n" );
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document.write( "       40n +  60m = 36000        (3)\r\n" );
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document.write( "       60n + 120m = 66000        (4)\r\n" );
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document.write( "Simplify one more time by dividing all the terms by 20\r\n" );
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document.write( "       2n +  3m = 1800          (5)\r\n" );
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document.write( "       3n +  6m = 3300          (6)\r\n" );
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document.write( "Multiply eq(5) by 2 (both sides). Keep eq(6) as is.\r\n" );
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document.write( "       4n +  6m = 3600          (7)\r\n" );
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document.write( "       3n +  6m = 3300          (8)\r\n" );
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document.write( "Subtract eq(8) from eq(7)\r\n" );
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document.write( "        n       = 300.\r\n" );
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document.write( "Then from eq(7)   4*300 + 6m = 3600,   6m = 3600 - 1200 = 2400,   m = 2400/6 = 400.\r\n" );
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document.write( "ANSWER.  300 stocks A  and  400 stocks B.\r\n" );
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document.write( "CHECK.   You can check my solution and my answer by substituting these values m and n into the original equations.\r\n" );
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document.write( "         Do it on your own.\r\n" );
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