document.write( "Question 104886: Write a system of two equations in two unknowns for each problem. Solve each system by substitution.\r
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document.write( "Tickets for a concert were sold to adults for $3 and to students for $2. If the total receipts were $824 and twice as many adult tickets as student tickets were sold, then how many of each were sold?\r
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document.write( "I'm struggling with how to set this problem up and solve it. Is it somthing like: 3a>2=824? \n" );
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Algebra.Com's Answer #76328 by oberobic(2304)![]() ![]() ![]() You can put this solution on YOUR website! Revenue = Price per Unit * Number of Units Sold \n" ); document.write( "R = PQ \n" ); document.write( "R for adults = Ra = 3A (where A = number of adults) \n" ); document.write( "R for student = Rs = 2B (where B = number of students) \n" ); document.write( "Ra + Rs = 824. \n" ); document.write( "Twice as many adult tickets were sold, means that A = 2B. \n" ); document.write( "Substituting, we have: \n" ); document.write( "Ra = 3A = 3(2B) = 6B. \n" ); document.write( "Rs = 2B \n" ); document.write( "Ra + Rs = 6B + 2B = 8B = 824 \n" ); document.write( "Dividing by 8 \n" ); document.write( "B = 824/8 = 103 \n" ); document.write( "B = number of student tickets \n" ); document.write( "A = 2B = 2(103) = 206 adult tickets sold \n" ); document.write( "ALWAYS check! \n" ); document.write( "3(206) + 2(103) = 824 \n" ); document.write( "618 +206 = 824 \n" ); document.write( "824=824 \n" ); document.write( "CHECK! \n" ); document.write( " |