document.write( "Question 1142578: A survey of athletes at a high school is conducted, and the following facts are discovered: 74% of the athletes are football players, 15% are basketball players, and 14% of the athletes play both football and basketball. An athlete is chosen at random from the high school: what is the probability that they are either a football player or a basketball player?
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Algebra.Com's Answer #763252 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "P(A OR B) = P(A) + P(B) - P(A AND B)\r\n" );
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document.write( "P(football OR basketball) = P(football) + P(basketball) - P(football AND basketball) = 74% + 15% - 14% = 75% = 0.75\r\n" );
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document.write( "Edwin
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