document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1142569>Question 1142569</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the 7th term of an arithmetic sequence is 1/2 and the 14th term is<BR>\n" );
document.write( "6 what is the 10th term? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #763243 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=763243\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The formula for the nth term of an arithmetic sequence is<BR>\n" );
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document.write( "x(n) = a +d(n-1), where is the first term, d is the common difference<BR>\n" );
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document.write( "x(7) = 1/2 = a +d(7-1)<BR>\n" );
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document.write( "1) a +6d = 1/2<BR>\n" );
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document.write( "x(14) = 6 = a +d(14-1)<BR>\n" );
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document.write( "2) a +13d = 6<BR>\n" );
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document.write( "equation 1, multiply both sides of = by 2<BR>\n" );
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document.write( "3) 2a +12d = 1<BR>\n" );
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document.write( "solve equation 2 for a<BR>\n" );
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document.write( "a = 6 -13d<BR>\n" );
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document.write( "substitute for a in equation 3<BR>\n" );
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document.write( "2(6-13d) +12d  = 1<BR>\n" );
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document.write( "12 -26d +12d = 1<BR>\n" );
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document.write( "-14d = -11<BR>\n" );
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document.write( "d = 11/14<BR>\n" );
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document.write( "a = 6 -13(11/14)<BR>\n" );
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document.write( "a = 84/14 -143/14 = -59/14<BR>\n" );
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document.write( "x(10) = -59/15 +11/14(9) = 40/14 = 20/7<BR>\n" );
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