document.write( "Question 1142544: A trader needs ₦300,000 to improve her business, she deposits ₦110,000 in her savings account at 5% per annum compound interest. she then adds ₦50,000 to her savings at the end of each year.
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document.write( "a) Find her total savings after 3 years.
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document.write( "b) By how much is her savings greater or lesser than ₦300,000 at the end of the third year. \n" );
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Algebra.Com's Answer #763235 by Theo(13342)![]() ![]() You can put this solution on YOUR website! she deposits 110,000. \n" ); document.write( "at end of first year, she has 110,000 * 1.05 = 115,500. \n" ); document.write( "she adds 50,000 to get 165,500. \n" ); document.write( "at end of second year, she has 165,500 * 1.05 = 173,775. \n" ); document.write( "she adds 50,000 to get 223,775. \n" ); document.write( "at end of third year, she has 223,775 * 1.05 - 234963.75. \n" ); document.write( "she adds 50,000 to get 284,963.75. \n" ); document.write( "she needs 300,000 \n" ); document.write( "she is short by 300,000 - 284,963.75 = 15,036.25\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |