document.write( "Question 1142544: A trader needs ₦300,000 to improve her business, she deposits ₦110,000 in her savings account at 5% per annum compound interest. she then adds ₦50,000 to her savings at the end of each year.
\n" ); document.write( "a) Find her total savings after 3 years.
\n" ); document.write( "b) By how much is her savings greater or lesser than ₦300,000 at the end of the third year.
\n" ); document.write( "

Algebra.Com's Answer #763235 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
she deposits 110,000.
\n" ); document.write( "at end of first year, she has 110,000 * 1.05 = 115,500.
\n" ); document.write( "she adds 50,000 to get 165,500.
\n" ); document.write( "at end of second year, she has 165,500 * 1.05 = 173,775.
\n" ); document.write( "she adds 50,000 to get 223,775.
\n" ); document.write( "at end of third year, she has 223,775 * 1.05 - 234963.75.
\n" ); document.write( "she adds 50,000 to get 284,963.75.
\n" ); document.write( "she needs 300,000
\n" ); document.write( "she is short by 300,000 - 284,963.75 = 15,036.25\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );