document.write( "Question 1142452: A chemist has two alcohol solutions of different strengths, 30% alcohol and 45% alcohol solutions respectively. how many cubic cm of each must be used so as to make a mixture of 30cc that will contain 39% alcohol? \n" ); document.write( "
Algebra.Com's Answer #763186 by Theo(13342)\"\" \"About 
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x = amount of 30% solution.
\n" ); document.write( "y = amount of 45% solution.\r
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\n" ); document.write( "\n" ); document.write( "x + y = 30
\n" ); document.write( ".3 * x + .45 * y = .39 * 30\r
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\n" ); document.write( "\n" ); document.write( "in the first equation, solve for y to get y = 30 - x.\r
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\n" ); document.write( "\n" ); document.write( "in the second euation, replace y with 30 - x to get .3 * x + .45 * (30 - x) = .39 * 30.\r
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\n" ); document.write( "\n" ); document.write( "simplify to get .3 * x + 13.5 - .45 * x = 11.7.\r
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\n" ); document.write( "\n" ); document.write( "combine like terms and subtract 13.5 from both sides of the equation to get -.15 * x = -1.8\r
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\n" ); document.write( "\n" ); document.write( "solve for x to get x = -1.8 / -.15 = 12\r
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\n" ); document.write( "\n" ); document.write( "y = 30 - x = 30 - 12 = 18.\r
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\n" ); document.write( "\n" ); document.write( "you have x = 12 and y = 18.\r
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\n" ); document.write( "\n" ); document.write( "x + y = 30
\n" ); document.write( ".3 * x + .45 * y = .3 * 12 + .45 * 18 = 3.6 + 8.1 = 11.7.
\n" ); document.write( "11.7 / 30 = .39\r
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\n" ); document.write( "\n" ); document.write( "solution looks good.\r
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\n" ); document.write( "\n" ); document.write( "solution is 12 cc of 30% solution and 18 cc of 45% solution are combined to make 30 cc of 39% solution.\r
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