document.write( "Question 1142427: A Weather sensor is shot from a platform into the air and allowed to fall back to the ground. Its height in meters is given by the equation h= -49t^2 + 18t + 5, where t is the time in seconds.
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document.write( "a) What is the maximum height of the sensor, and at what time does it occur?
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document.write( "b) When does the Rocket return to the ground?
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document.write( "c) At what times is the sensor 15 meter above the ground?
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document.write( "d) How high is the sensor after 1.5 seconds? \n" );
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Algebra.Com's Answer #763124 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! A Weather sensor is shot from a platform into the air and allowed to fall back to the ground. Its height in meters is given by the equation h= -49t^2 + 18t + 5, where t is the time in seconds. \n" ); document.write( "a) What is the maximum height of the sensor, and at what time does it occur? \n" ); document.write( "Max height is the vertex of the parabola, at t = -b/2a \n" ); document.write( "t = -18/-98 = 9/49 seconds. \n" ); document.write( "h(t) = -49t^2 + 18t + 5 \n" ); document.write( "h(9/49) = -49*(81/2401) + 18*9/49 + 5 \n" ); document.write( "= -81/49 + 162/49 + 245/49 \n" ); document.write( "= 336/49 = 48/7 meters \n" ); document.write( "========================== \n" ); document.write( "b) When does the Rocket return to the ground? \n" ); document.write( "When h(t) = 0 \n" ); document.write( "-49t^2 + 18t + 5 = 0 \n" ); document.write( "Solve for t \n" ); document.write( "========================= \n" ); document.write( "c) At what times is the sensor 15 meter above the ground? \n" ); document.write( "At no time. \n" ); document.write( "========================= \n" ); document.write( "d) How high is the sensor after 1.5 seconds? \n" ); document.write( "Find h(1.5) \n" ); document.write( "-------------------------------------------------- \n" ); document.write( "The function is probably h(t) = -4.9t^2 + 18t + 5, not 49t^2 \n" ); document.write( "------------ \n" ); document.write( "If so, do the same calculations using 4.9. \n" ); document.write( " \n" ); document.write( " |