document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1142417>Question 1142417</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A crossection of a tunnel is in the shape of a major segment of a circle of radius 1m on a chord of length 1.6m. Calculate the angle subtend by the major arc </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #763120 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=763120\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A crossection of a tunnel is in the shape of a major segment of a circle of radius 1m on a chord of length 1.6m.<BR>\n" );
document.write( " Calculate the angle subtend by the major arc<BR>\n" );
document.write( ":<BR>\n" );
document.write( "We can find the angle of the minor arc using half right triangle formed by the the radius and the half the chord <BR>\n" );
document.write( "sin(A) = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=.8%2F1 ALIGN=MIDDLE  ALT=\".8%2F1\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "A = 53.13 degrees<BR>\n" );
document.write( "therefore the minor arc is 2 * 53.13 = 106.26 degrees<BR>\n" );
document.write( "and the major arc is:<BR>\n" );
document.write( "360 - 106.26 = 253.74 degrees </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );