document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=15349>Question 15349</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In reference to Inverse Functions:  How do you determine when to use the \"short cut\" method when trying to find the inverse of a function?  For example, f(x) y = (x3+8)/3 so, we cubed it, added 8, and then divided by 3.  If you undo it in reverse order (multiply 3, minus 8, cube root) it becomes the inverse. <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=f%5E%28-1%29%28x%29+=+root%283%2C3x-8%29 ALIGN=MIDDLE  ALT=\"f%5E%28-1%29%28x%29+=+root%283%2C3x-8%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >  Why won't this work on all the problems? Thank you in advance!      </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #7631 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=7631\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I'll just BET that this question was raised by one of MY own students, with reference to #17 on page 329 of my College Algebra: One Step at a Time!!!  Am I right???  Congratulations on a GREAT question, and thanks to Kenny for a great answer.  \"Invertible\" steps!  That's what you call it. \r<BR>\n" );
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document.write( "R^2 at Seminole Community College<BR>\n" );
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