document.write( "Question 1142387: A ship made a trip of 232 mi in 16 h. The ship traveled the first 96 mi at a constant rate before increasing its speed by 5 mph. It traveled another 136 mi at the increased speed. Find the rate of the ship for the first 96 mi \n" ); document.write( "
Algebra.Com's Answer #763083 by ikleyn(52905)\"\" \"About 
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document.write( "Let x be the rate for the first 96 miles (in miles per hour).\r\n" );
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document.write( "Then the rate for another 136 miles is (x+5) miles per hour, according to the condition.\r\n" );
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document.write( "The time spent for the first 96 miles is  \"96%2Fx\" hours.\r\n" );
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document.write( "The time spent for the other 136 miles is  \"136%2F%28x%2B5%29\" hours.\r\n" );
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document.write( "The total time equation is\r\n" );
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document.write( "\"96%2Fx\" + \"136%2F%28x%2B5%29\" = 16  hours.\r\n" );
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document.write( "To solve the equation, first multiply both sides by x*(x+5).\r\n" );
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document.write( "Then simplify and get a quadratic equation in the standard form.\r\n" );
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document.write( "Solve the quadratic equation using the quadratic formula or factoring (choose what works better for you).\r\n" );
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document.write( "The positive root of the quadratic equation will be your answer.\r\n" );
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document.write( "ANSWER.  At the end, you should get the rate of 12 miles per hour.\r\n" );
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document.write( "CHECK.   \"96%2F12\" + \"136%2F%2812%2B5%29\" = 8 + 8 = 16 hours.   ! Correct !\r\n" );
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\n" ); document.write( "\n" ); document.write( "If you want to see many other similar solved problems, look into the lesson\r
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