document.write( "Question 1142283: One positive number exceeds by 5 .The sum of their squares is 193.find the numbers
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Algebra.Com's Answer #763010 by Theo(13342)![]() ![]() You can put this solution on YOUR website! x is the value of one of the numbers. \n" ); document.write( "y is the value of the other number.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = y + 5 is one of your equations. \n" ); document.write( "x^2 + y^2 = 193 is the other of your equations.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "in the second equation, replace x with y + 5 to get: \n" ); document.write( "(y + 5)^2 + y^2 = 193 \n" ); document.write( "simplify to get: \n" ); document.write( "y^2 + 10y + 25 + y^2 = 193 \n" ); document.write( "combine like terms to get: \n" ); document.write( "2y^2 + 10y + 25 = 193 \n" ); document.write( "subtract 193 from both sides of the equation to get: \n" ); document.write( "2y^2 + 10y - 168 = 0 \n" ); document.write( "divide both sides of this equation by 2 to get: \n" ); document.write( "y^2 + 5y - 84 = 0 \n" ); document.write( "factor to get: \n" ); document.write( "(y + 12) * (y - 7) = 0 \n" ); document.write( "solve for y to get: \n" ); document.write( "y = -12 or y = 7\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "value of y has to be positive, so y = 7 is a possible solution. \n" ); document.write( "x = y + 5, therefore x = 12 \n" ); document.write( "your number appear to be 12 and 7. \n" ); document.write( "12 - 7 = 5, which satisfies one of the requirements. \n" ); document.write( "12^2 + 7^2 = 144 + 49 = 193, which satisfies the other requirement.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your solution is that the numbers are 7 and 12.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |