document.write( "Question 1142293: Suppose that a factory's cost (in dollars) for making x cars is
\n" );
document.write( "C(x)=5410x+5510
\n" );
document.write( "Then the average cost per car is
\n" );
document.write( "C'(x)=5410x+5510/x
\n" );
document.write( "How many cars must the factory make each day to ensure the average cost per car is no more than $5600? \n" );
document.write( "
Algebra.Com's Answer #762995 by rothauserc(4718) You can put this solution on YOUR website! (5410x +5510) / x = 5600 \n" ); document.write( ": \n" ); document.write( "5410x +5510 = 5600x \n" ); document.write( ": \n" ); document.write( "190x = 5510 \n" ); document.write( ": \n" ); document.write( "x = 29 \n" ); document.write( ": \n" ); document.write( "******************************************* \n" ); document.write( "The factory must make at most 29 cars daily \n" ); document.write( "******************************************* \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( " |