document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1142254>Question 1142254</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A pilot flies 1050 mi with a tailwind of 20mph. Against the wind, he flies only 850 mi in the same amount of time. What is the speed of the plane in still air? </SPAN>\n" );
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document.write( "Time is distance divided by rate.<br><BR>\n" );
document.write( "Since the times with and against the wind are the same, time is also the DIFFERENCE in distances divided by the DIFFERENCE in rates.<br><BR>\n" );
document.write( "The difference in the two rates is twice the wind speed (because the wind speed adds to the speed in one direction and subtracts from it in the other direction).<br><BR>\n" );
document.write( "So the difference in rates is 40mph; the difference in distances is 200 miles.  So the time for each flight is 200/40 = 5 hours.<br><BR>\n" );
document.write( "So the speed of the plane with the wind is 1050/5 = 210mph; that makes the speed of the plane in still air 210-20 = 190mph. </SPAN>\n" );
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