document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=104858>Question 104858</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 6(w-5)-3w=w+10 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #76297 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=76297\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I presume that you need to solve for w?<BR>\n" );
document.write( "6(w-5)-3w = w+10 First, apply the distributive property to the left side.<BR>\n" );
document.write( "6w-30-3w = w+10 Now combine the variable, w.<BR>\n" );
document.write( "6w-3w-30 = w+10<BR>\n" );
document.write( "3w-30 = w+10 Subtract w from both sides.<BR>\n" );
document.write( "2w-30 = 10 Now add 30 to both sides.<BR>\n" );
document.write( "2w = 40 Finally, divide both sides by 2.<BR>\n" );
document.write( "w = 20<BR>\n" );
document.write( "Check:<BR>\n" );
document.write( "6(w-5)-3w = w+10 Substitute w = 20<BR>\n" );
document.write( "6(20-5)-3(20)= 20+10 Simpllify.<BR>\n" );
document.write( "6(15)-60 = 30<BR>\n" );
document.write( "90-60 = 30<BR>\n" );
document.write( "30 = 30 OK!  </SPAN>\n" );
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