document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=104853>Question 104853</A>: <I><SPAN STYLE=\"word-break: break-all;\"> My son and I have been working on this for hours<BR>\n" );
document.write( "twice the supplement of the complement of an angle is 60 degrees more than the supplement of the angle. find the complement of the angle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #76295 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=76295\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First, let's find the angle, which we can call angle A, then we can find its complement (90-A) to answer the problem.<BR>\n" );
document.write( "The supplement of A is 180-A and the complement of A is 90-A<BR>\n" );
document.write( "From the problem description, we can write:<BR>\n" );
document.write( "2(180-(90-A)) = (180-A)+60 Simplify this and solve for A<BR>\n" );
document.write( "2(180-90+A) = 180+60-A<BR>\n" );
document.write( "2(90+A) = 240-A<BR>\n" );
document.write( "180+2A = 240-A Add A to both sides of the equation.<BR>\n" );
document.write( "180+3A = 240 Now subtract 240 from both sides.<BR>\n" );
document.write( "3A = 60 Finally, divide both sides by 3.<BR>\n" );
document.write( "A = 20 degrees.  Now we can find the complement of A (90-A) as required by the problem.<BR>\n" );
document.write( "90-A = 90-20 = 70 degrees.<BR>\n" );
document.write( "The solution is:<BR>\n" );
document.write( "The complement of the angle is 70 degrees.\r<BR>\n" );
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