document.write( "Question 104853: My son and I have been working on this for hours
\n" ); document.write( "twice the supplement of the complement of an angle is 60 degrees more than the supplement of the angle. find the complement of the angle
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Algebra.Com's Answer #76294 by edjones(8007)\"\" \"About 
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let the angle be x
\n" ); document.write( "complement=90-x
\n" ); document.write( "supplement=180-x
\n" ); document.write( "supplement of the complement=(180-(90-x))
\n" ); document.write( "So, 2(180-(90-x))=60+180-x
\n" ); document.write( "2(180-90+x)=240-x
\n" ); document.write( "360-180+2x=240-x
\n" ); document.write( "3x=240-360+180
\n" ); document.write( "3x=60
\n" ); document.write( "x=20 degrees
\n" ); document.write( "Check:
\n" ); document.write( "compliment (20)=70
\n" ); document.write( "suppliment (20)=160
\n" ); document.write( "suppliment of compliment (70)=110
\n" ); document.write( "2*110=60+160
\n" ); document.write( "220=220
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\n" ); document.write( "Ed\r
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