document.write( "Question 104853: My son and I have been working on this for hours
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document.write( "twice the supplement of the complement of an angle is 60 degrees more than the supplement of the angle. find the complement of the angle \n" );
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Algebra.Com's Answer #76294 by edjones(8007)![]() ![]() You can put this solution on YOUR website! let the angle be x \n" ); document.write( "complement=90-x \n" ); document.write( "supplement=180-x \n" ); document.write( "supplement of the complement=(180-(90-x)) \n" ); document.write( "So, 2(180-(90-x))=60+180-x \n" ); document.write( "2(180-90+x)=240-x \n" ); document.write( "360-180+2x=240-x \n" ); document.write( "3x=240-360+180 \n" ); document.write( "3x=60 \n" ); document.write( "x=20 degrees \n" ); document.write( "Check: \n" ); document.write( "compliment (20)=70 \n" ); document.write( "suppliment (20)=160 \n" ); document.write( "suppliment of compliment (70)=110 \n" ); document.write( "2*110=60+160 \n" ); document.write( "220=220 \n" ); document.write( ". \n" ); document.write( "Ed\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |