document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1142201>Question 1142201</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One hundred teachers attended a seminar on mathematical problem solving. The attitudes of a representative sample of 12 of the teachers were measured before and after the seminar. A positive number for change in attitude indicates that a teacher's attitude toward math became more positive. The 12 change scores are as follows: \r<BR>\n" );
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document.write( "3; 8;  -  1; 2; 0; 5;  -  3; 1;  -  1; 6; 5;  -  2\r<BR>\n" );
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document.write( "What is the mean change score? \r<BR>\n" );
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document.write( "What is the standard deviation for this sample? \r<BR>\n" );
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document.write( "What is the median change score? \r<BR>\n" );
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document.write( "Find the change score that is 2.2 standard deviations below the mean. \r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #762916 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=762916\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> mean is 1.917<BR>\n" );
document.write( "sd is 3.502<BR>\n" );
document.write( "median is middle of ordered numbers -3/-2/-1/-1/0/1/2/3/5/5/6/8, here between the 6th and the 7th since with even number sample, there is not a unique middle.  This would be 1.5<BR>\n" );
document.write( "2.2 sd s below the mean is 1.92-2.2(3.5)=1.92-7.70 or -5.78 </SPAN>\n" );
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