document.write( "Question 1142232: In a certain neighborhood of 100 families, 60 get their news from TV, 54 from the local paper, and 20 from both sources. If a family is selected at random, what is the probability that this family does not use any one of these sources for the news? \n" ); document.write( "
Algebra.Com's Answer #762905 by ikleyn(52848)\"\" \"About 
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document.write( "The probability that a randomly selected family gets news for one of the two sources is\r\n" );
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document.write( "    P = \"60%2F100\" + \"54%2F100\" - \"20%2F100\" = \"94%2F100\".\r\n" );
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document.write( "The probability under the question is the COMPLEMENT to it, i.e.\r\n" );
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document.write( "    1 - \"94%2F100\" = \"6%2F100\" = \"3%2F50\" = 6%.    ANSWER\r\n" );
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