document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1142163>Question 1142163</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A grocer wishes to mix some nuts worth $.90 per pound with some nuts worth $1.60 per pound to make 175 pounds of a mixture that is worth $1.3o per pound. How much of each should she use? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #762841 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=762841\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Try this for an easier and faster way to solve \"mixture\" problems like this.<br><BR>\n" );
document.write( "(1) 1.30 is 4/7 of the way from 0.90 to 1.60. (0.90 to 1.60 is .70; 0.90 to 1.30 is .40; .40/.70 = 4/7)<BR>\n" );
document.write( "(2) Therefore 4/7 of the mixture must be the more expensive nuts.<br><BR>\n" );
document.write( "ANSWER: 4/7 of 175 pounds = 100 pounds of the $1.60 per pound nuts; the rest, 75 pounds, of the $0.90 per pound nuts.<br><BR>\n" );
document.write( "The idea behind this method is that the ratio in which the two ingredients must be mixed is exactly determined (in a linear fashion) by where the target price per pound lies between the per pound prices of the two ingredients. </SPAN>\n" );
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