document.write( "Question 1142129: 3 litre of oil and 30 litre of petrol cost R45 while 7 litre and 15 litre of petrol cost R40.Calculate the price of the oil. \n" ); document.write( "
Algebra.Com's Answer #762803 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! let a = the price of oil \n" ); document.write( "let b = the price of petrol \n" ); document.write( ": \n" ); document.write( "write an equation for each statement \n" ); document.write( ": \n" ); document.write( "3 litre of oil and 30 litre of petrol cost R45 \n" ); document.write( "3a + 30b = 45 \n" ); document.write( ": \n" ); document.write( "while 7 litre and 15 litre of petrol cost R40. \n" ); document.write( "7a + 15b = 40 \n" ); document.write( ": \n" ); document.write( "Calculate the price of the oil. \n" ); document.write( "Use elimination, multiply the 2nd equation by 2, subtract the 1st equation \n" ); document.write( "14a + 30b = 80 \n" ); document.write( " 3a + 30b = 45 \n" ); document.write( "---------------subtraction eliminates b, find a \n" ); document.write( "11a + 0 = 35 \n" ); document.write( "a = 35/11 \n" ); document.write( "a = $3.18 for oil \n" ); document.write( ": \n" ); document.write( "Use the 1st equation to find b, \n" ); document.write( "3(3.18) + 30b = 45 \n" ); document.write( "9.54 + 30b = 45 \n" ); document.write( "30b = 45 - 9.54 \n" ); document.write( "30b = 35.46 \n" ); document.write( "b = 35.46/30 \n" ); document.write( "b = $1.18 for petrol \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "See if these awkward solutions check out in the 2nd equation \n" ); document.write( "7(3.18) + 15(1.18) = \n" ); document.write( "22.26 + 17.70 = 39.96 ~ 40 \n" ); document.write( " |