document.write( "Question 1142098: an investor invested a total of $1,800 in two mutual funds. One fund earned a 6% profit while the other earned a 3% profit. If the investor's profit was $69, how much was invested in each mutual fund? \n" ); document.write( "

Algebra.Com's Answer #762764 by greenestamps(13200) $\"\"$ $\"About$

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Here is a non-algebraic method for solving mixture problems like this that can get you to the answer much faster than the traditional algebraic method if you understand how to use it (and if an algebraic solution is not required).

\n" ); document.write( "(1) Determine the amounts of interest if the entire $1800 were invested at 3% and at 6%.
\n" ); document.write( "1800*.03 = 54
\n" ); document.write( "1800*,06 = 108
\n" ); document.write( "(2) Consider the three interest amounts on a number line -- 54, 69, and 108.
\n" ); document.write( "(3) Find what fraction of the way from 54 to 108 the number 69 is.
\n" ); document.write( "108-54 = 54; 69-54 = 15.
\n" ); document.write( "69 is 15/54 = 5/18 of the way from 54 to 108.
\n" ); document.write( "(4) That fraction is the fraction of the mixture that is at the higher rate.

\n" ); document.write( "ANSWER: 5/18 of $1800 = $500 at 6%; the rest, $1300, at 3%. \n" ); document.write( "

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