document.write( "Question 1142094: The graph below shows y=f(x). Show the final graph after the transformations of y=-2f(-x+3)+4.\r
\n" ); document.write( "\n" ); document.write( "Link to diagram : http://tinypic.com/r/2wp8rw3/9\r
\n" ); document.write( "\n" ); document.write( "Thank you in advance
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Algebra.Com's Answer #762762 by greenestamps(13198)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "You can do the graphing....

\n" ); document.write( "You need to determine what the sequence of transformations does to each \"vertex\" of the graph.

\n" ); document.write( "You first need to rewrite the transformation so that the expression in parentheses is of the form (x-a):

\n" ); document.write( "\"y+=+-2f%28-x%2B3%29%2B4\" --> \"y+=+-2f%28-%28x-3%29%29%2B4\"

\n" ); document.write( "In that form, you can see the sequence of transformations is

\n" ); document.write( "(1) (x-3) --> horizontal shift of 3
\n" ); document.write( "(2) -(x-3) --> reflect in y-axis
\n" ); document.write( "(3) -2f(-(x-3)) --> vertical stretch by -2 (reflect in x-axis and double)
\n" ); document.write( "(4) -2f(-(x-3))+4 --> vertical shift of 4

\n" ); document.write( "Now perform that sequence of transformations to each given point to find the image under the given transformation.
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document.write( "        A       B       C       D       E       F\r\n" );
document.write( " (0)  (-1,3)  (2,0)   (3,-3)  (4,2)   (6,1)   (8,-2)\r\n" );
document.write( " (1)   (2,3)  (5,0)   (6,-3)  (7,2)   (9,1)   (11,-2)\r\n" );
document.write( " (2)  (-2,3) (-5,0)  (-6,-3) (-7,2)  (-9,1)  (-11,-2)\r\n" );
document.write( " (3) (-2,-6) (-5,0)   (-6,6) (-7,-4) (-9,-2)  (-11,4)\r\n" );
document.write( " (4) (-2,-2) (-5,4)  (-6,10)  (-7,0)  (-9,2)  (-11,8)

\n" ); document.write( "Those are the coordinates of the images of the original points under the given transformation.
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