document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=104822>Question 104822</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 5(y+3)-2y=6 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #76276 by </B><A HREF=/tutors/aboutme.mpl?userid=cheesey><B>cheesey(22)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=cheesey><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=76276\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Distribute the 5, then collect your y-terms and solve for y.\r<BR>\n" );
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document.write( "5y+15-2y = 6 => 5y-2y + 15 = 6 => 3y +15 = 6<BR>\n" );
document.write( "subtract 15 from both sides\r<BR>\n" );
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document.write( "3y +15 - 15 = 6 - 15<BR>\n" );
document.write( "3y = -9 (divide both sides by 3)<BR>\n" );
document.write( "y = -3 </SPAN>\n" );
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