document.write( "Question 1142053: Show that cos 2pi/9 is a root of the equation 8x^3 - 6x + 1=0 \n" ); document.write( "
Algebra.Com's Answer #762717 by math_helper(2461)![]() ![]() You can put this solution on YOUR website! I think you meant to say \"Show it is NOT a root.\" \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "It is the very definition of a transcendental number.\r \n" ); document.write( "\n" ); document.write( "---------------- \n" ); document.write( "EDIT: Oh, disregard, I just noticed cos in front, you should really write cos(2pi/9) \n" ); document.write( "----------------\r \n" ); document.write( "\n" ); document.write( "cos(2pi/9) is approx 0.76604444\r \n" ); document.write( "\n" ); document.write( "Plugging this into the equation gives 0 out, therefore cos(2pi/9) is a root.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |