document.write( "Question 104808This question is from textbook
\n" ); document.write( ": Jo has 37 coins (all nickels, dimes and quarters) worth $5.50. She has 4 more quarters than nickels. How many dimes does she have? \n" ); document.write( "
Algebra.Com's Answer #76271 by rossiv53(27)\"\" \"About 
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Let amount of nickels = n, amount of quarters = (n+4), and amount of dimes = (37-n).\r
\n" ); document.write( "\n" ); document.write( "So, \".05n+%2B.25%28n%2B4%29%2B.10%2837-n%29+=+5.50\"
\n" ); document.write( "\".05n%2B.25n%2B1.00%2B3.70-.10n+=+5.50\"
\n" ); document.write( "\".20n%2B4.70+=+5.50+\"
\n" ); document.write( "\".20n%2B4.70+=+5.50\"
\n" ); document.write( "\".20n%2B4.70-4.70+=+5.50-4.70\"
\n" ); document.write( "\".20n+=.80\"
\n" ); document.write( "\"n+=+4\"
\n" ); document.write( "So, 4 nickels, 8 quarters, and 33 dimes.\r
\n" ); document.write( "\n" ); document.write( "Good Luck!
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