document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1142057>Question 1142057</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What, approximately, is log2 32? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #762704 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=762704\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> log2(32) = y if and only if 2^y = 32.\r<BR>\n" );
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document.write( "2^y = 32 when y = 5.\r<BR>\n" );
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document.write( "you get 2^5 = 32\r<BR>\n" );
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document.write( "you can confirm this is true by using your calculator.\r<BR>\n" );
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document.write( "you can also solve for y by using the lob base conversion formula of:\r<BR>\n" );
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document.write( "log2(32) = log10(32) / log10(2) which becomes log(32) / log(2) when using your calculator, because the log function assumes log to the base of 10.\r<BR>\n" );
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document.write( "you will see that log(32) / log(2) = 5.\r<BR>\n" );
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