document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1142037>Question 1142037</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Sarah has 16 pounds of soup that is 1/4 chicken broth. How much chicken broth must she add to increase the chicken broth content to 1/3 ?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #762697 by </B><A HREF=/tutors/aboutme.mpl?userid=VFBundy><B>VFBundy(438)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=VFBundy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=VFBundy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=762697\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Broth/soup = 1/4.  We are given the soup is 16 lbs., so to get 1/4 broth, that means the broth must be 4 lbs.  (Because broth/soup = 4/16 = 1/4.)<BR>\n" );
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document.write( "To find out how much broth we must add to get a soup that is 1/3 broth:<BR>\n" );
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document.write( "Broth/soup = (4+x)/(16+x) = 1/3<BR>\n" );
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document.write( "Cross-multiply:<BR>\n" );
document.write( "3(4+x) = 1(16+x)<BR>\n" );
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document.write( "12 + 3x = 16 + x<BR>\n" );
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document.write( "2x = 4<BR>\n" );
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document.write( "x = 2<BR>\n" );
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document.write( "Sarah must add 2 lbs. of chicken broth.  This will give her 6 total lbs. of broth and 18 total lbs. of soup, for a soup that is 1/3 broth.\r<BR>\n" );
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