document.write( "Question 1142030:  Provide a sketch for this information.
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document.write( "From a horizontal distance of 10.5km, a pilot observes that that the angles of depression of the top and base of a control tower are 36degrees and 41degrees respectively. Calculate height of the control tower \n" );
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| Algebra.Com's Answer #762685 by Theo(13342)     You can put this solution on YOUR website! here's your sketch.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "  \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "point A is the airplane. \n" ); document.write( "point F is the top of the tower. \n" ); document.write( "point C is the bottom of the tower.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "AB is the horizontal distance from the plane to the tower at the level of the plane.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "DC is the horizontal distance from the plane to the tower at the level of the bottom of the tower.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "EF is the horizontal distance from the plane to the tower at the level of the top of the tower.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "ABCD is the rectangle formed.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "angle BAF is the angle of depression from the plane to the top of the tower.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "angle BAC is the angle of depression from the plane to the bottom of the tower.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "AF forms the diagonal of rectangle ABFE.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "AC forms the diagonal of rectangle ABCD.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "angle AFE is equal to angle BAF because they form alternate interior angles of parallel lines AB and EF.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "angle ACD is equal to angle BAC because they form alternate interior angles of parallel lines AB and DC.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "two triangles formed are triangles AFE and ACD.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the base of both of these triangles (EF and DC) are each 10.5 kilometers in length.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the length of BF is equal to y.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the length of FC is equal to x.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the length of BC is equal to x + y.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "in triangle AFE, tangent of angle AFE is equal to y / 10.5.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "in triangle ACD, tangent of angle ACD is equal to (x + y) / 10.5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "since angle AFE is equal to 36 degrees, you get tan(36) = y / 10.5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "since angle ACED is equal to 41 degrees, you get tan(41) = (x + y) / 10.5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve for y in the first equation of tan(36) = y / 10.5 to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y = 10.5 * tan(36).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "multiply both sides of the second equation of tan(41) = (x + y) / 10.5 to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "10.5 * tan(41) = x + y\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "replace y with 10.5 * tan(36) to make that equation become:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "10.5 * tan(41) = x + 10.5 * tan(36)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "subtract 10.5 * tan(36) from both sides of that equation to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "10.5 * tan(41) - 10.5 * tan(36) = x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you now have:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y = 10.5 * tan(36).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = 10.5 * tan(41) - 10.5 * tan(36)..\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve for each to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y = 7.628696544.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = 1.498814203.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that makes x + y = 9.127510747.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the height of the tower is equal to x.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "therefore, your solution is that the height of the tower is equal to 1.498814203 kilometers.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "sounds awfully high for a tower, but that's what i get from my understanding of the information given.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |