document.write( "Question 1142022: On a particular day, the wind added 4 miles per hour to Alfonso's rate when he was cycling with the wind and subtracted 4 miles per hour from his rate on his return trip. Alfonso found that in the same amount of time he could cycle 57 miles with the wind, he could go only 33 miles against the wind.\r
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Algebra.Com's Answer #762682 by ikleyn(52797) $\"\"$ $\"About$

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document.write( "The time equation for this kinematic problem is this\r\n" );
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document.write( "     = .\r\n" );
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document.write( "where x is the speed at no wind, in miles per hour.\r\n" );
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document.write( "To solve the equation, cross-multiply\r\n" );
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document.write( "    57*(x-4) = 33*(x+4),\r\n" );
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document.write( "simplify and get\r\n" );
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document.write( "    57x - 33x = 33*4 + 57*4\r\n" );
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document.write( "    x =  = 15 miles per hour.     ANSWER\r\n" );
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