document.write( "Question 1141992: A movie theater has a seating capacity of 207. The theater charges $5.00 for children, $7.00 for students, and $12.00 of adults. There are half as many adults as there are children. If the total ticket sales was $ 1498, How many children, students, and adults attended? \n" ); document.write( "

Algebra.Com's Answer #762649 by ikleyn(53751) $\"\"$ $\"About$

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document.write( "Let \"a\" be the number of adults;  then the number of children is  (2a).\r\n" );
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document.write( "The number of students is the rest, (207-a-2a) = 207-3a.\r\n" );
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document.write( "The \"money\" equation is\r\n" );
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document.write( "    12a + 5*(2a) + 7*(207-3a) = 1498  dollars.\r\n" );
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document.write( "Simplify and solve for \"a\".\r\n" );
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document.write( "    12a + 10a + 7*207 - 21a = 1498,\r\n" );
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document.write( "    a = 1498 - 7*207\r\n" );
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document.write( "    a = 49.\r\n" );
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document.write( "ANSWER.  49 adults;  2*49 = 98 children  and  (207-3*49) = 60 students.\r\n" );
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\n" ); document.write( "\n" ); document.write( "This problem is to be solved using one equation in one unknown.\r
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\n" ); document.write( "\n" ); document.write( "If you want to see many other similar solved problems, look into the lessons\r
\n" ); document.write( "\n" ); document.write( " - Advanced word problems to solve using a single linear equation\r
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