document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1141977>Question 1141977</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Mike invested $1200, part at 8% and the rest at 6% per year. The interest earned after one year was $88. How much did mike invested at each rate? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #762629 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=762629\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Here is an easy alternative to the standard algebraic solution method shown by the other tutor; this method can be used on a wide variety of \"mixture\" problems.<br><BR>\n" );
document.write( "(1) $1200 all at 6% would give $72 interest; all at 8% would give $96 interest.<br><BR>\n" );
document.write( "(2) The actual interest, $88, is 2/3 of the way from $72 to $96.  (Picture the three interest amounts $72, $88, and $96 on a number line; 88 is 2/3 of the way from 72 to 96.)<br><BR>\n" );
document.write( "(3) Therefore 2/3 of the total investment needs to be at the higher rate.<br><BR>\n" );
document.write( "ANSWER: 2/3 of $1200 = $800 at 8%; 1/3 of $1200 = 400 at 6%.<br><BR>\n" );
document.write( "CHECK: 400(.06)+800(.08) = 24+64 = 88 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );