document.write( "Question 1141977: Mike invested $1200, part at 8% and the rest at 6% per year. The interest earned after one year was $88. How much did mike invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #762620 by VFBundy(438)\"\" \"About 
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8% rate investment:
\n" ); document.write( "Principal = p
\n" ); document.write( "Rate = 0.08
\n" ); document.write( "Interest = 0.08p
\n" ); document.write( "
\n" ); document.write( "6% rate investment:
\n" ); document.write( "Principal = 1200 - p
\n" ); document.write( "Rate = 0.06
\n" ); document.write( "Interest = 0.06(1200 - p)
\n" ); document.write( "
\n" ); document.write( "0.08p + 0.06(1200 - p) = 88
\n" ); document.write( "
\n" ); document.write( "0.08p + 72 - 0.06p = 88
\n" ); document.write( "
\n" ); document.write( "0.02p + 72 = 88
\n" ); document.write( "
\n" ); document.write( "0.02p = 16
\n" ); document.write( "
\n" ); document.write( "p = 800
\n" ); document.write( "
\n" ); document.write( "8% rate investment:
\n" ); document.write( "Principal = p = $800
\n" ); document.write( "
\n" ); document.write( "6% rate investment:
\n" ); document.write( "Principal = 1200 - p = 1200 - 800 = $400 \n" ); document.write( "
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