document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1141946>Question 1141946</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two numbers sum to 49.<BR>\n" );
document.write( "Twice the first subtracted from the second is 7. Find the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #762581 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=762581\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a is the first number.<BR>\n" );
document.write( "b is the second number.\r<BR>\n" );
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document.write( "a + b = 49\r<BR>\n" );
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document.write( "b - 2a = 7\r<BR>\n" );
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document.write( "solve for b in the second equation to get b = 2a + 7\r<BR>\n" );
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document.write( "replace b with 2a + 7 in the first equation to get a + 2a + 7 = 49\r<BR>\n" );
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document.write( "combine like terms to get 3a + 7 = 49\r<BR>\n" );
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document.write( "subtract 7 from both sides of the equation to get 3a = 42\r<BR>\n" );
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document.write( "solve for a to get a = 14\r<BR>\n" );
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document.write( "since a + b = 49, then b must be equal to 35.\r<BR>\n" );
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document.write( "a + b = 49 becomes 14 + 35 = 49 which becomes 49 = 49 which is true.\r<BR>\n" );
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document.write( "b - 2a = 7 becomes 35 - 2 * 14 = 7 which becomes 35 - 28 = 7 which becomes 7 = 7 which is true.\r<BR>\n" );
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document.write( "solution looks good.\r<BR>\n" );
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document.write( "solution is the first number = 14 and the second number = 35.\r<BR>\n" );
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